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Statement : If two half reaction with el...

Statement : If two half reaction with electrode potential `E_(1)^(@)` and `E_(2)^(@)` gives a third reaction then,
`DeltaG_(3)^(@) = DeltaG_(1)^(@) + DeltaG_(2)^(@)`
Explanation : `E_(3)^(@) = E_(1)^(@) + E_(2)^(@)`

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The correct Answer is:
A

In such case `E^(@)` are not additive.
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Prove that for two half reactions having potentials E_(1) and E_(2) which are combined to yield a third half reaction, having a potential E_(3) , E_(3)=(n_(1)E_(1)+n_(2)E_(2))/n_(3)

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Assertion (A): For four half - cell reactions involving different number of electrons, E_(4)=E_(1)+E_(2)+E_(3) Reaction (R): DeltaG_(4)=DeltaG_(1)+DeltaG_(2)+DeltaG_(3)

Read the following passage for the evaluation of E^(@) when different number of electrons are involved. Consider addition of the following half reactions (1) Fe^(3+)(aq)+3e^(-)rarr Fe(s) E_(1)^(@)=0.45V (2) Fe(s)rarr Fe^(2+)(aq)+2e^(-) E_(2)^(@)=-0.04V (3) Fe^(3+)(aq)+e^(-)rarr Fe^(2+)(aq) E_(3)^(@)= ? Because half-reactions (1) and (2) contains a different number of electrons, the net reaction (3) is another half-reaction and E_(3)^(@) can't be obtained simply by adding E_(1)^(@) and E_(3)^(@) . The free - energy changes however, are additive because G is a state function : Delta G_(3)^(@)=Delta G_(1)^(@)+Delta G_(2)^(@) For the reactions (1) MnO_(4)^(-)+8H^(+)+5e^(-)rarr Mn^(2)+4H_(2)O E^(@)=1.51 V (2) MnO_(2)+4H^(+)+2e^(-)rarr Mn^(2+)2H_(2)O E^(@)=1.32 then for the reaction (3) MnO_(4)^(-)+4H^(+)+3e^(-)rarrMnO_(2)+2H_(2)O, E^(@) is

For a spontaneous reaction the DeltaG , equilibrium constant (K) and E_("cell")^(@) will be respectively

Read the following passage for the evaluation of E^(@) when different number of electrons are involved. Consider addition of the following half reactions (1) Fe^(3+)(aq)+3e^(-)rarr Fe(s) E_(1)^(@)=0.45V (2) Fe(s)rarr Fe^(2+)(aq)+2e^(-) E_(2)^(@)=-0.04V (3) Fe^(3+)(aq)+e^(-)rarr Fe^(2+)(aq) E_(3)^(@)= ? Because half-reactions (1) and (2) contains a different number of electrons, the net reaction (3) is another half-reaction and E_(3)^(@) can't be obtained simply by adding E_(1)^(@) and E_(3)^(@) . The free - energy changes however, are additive because G is a state function : Delta G_(3)^(@)=Delta G_(1)^(@)+Delta G_(2)^(@) Standard electrode potential for the half-cell Fe^(3+)//Fe^(2+) of the reaction (3) is :

P BAHADUR-ELECTROCHEMISTRY-Exercise (9) ADVANCED NUMERICAL PROBLEMS
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