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A lead storage cell is discharged which ...

A lead storage cell is discharged which causes the `H_(2)SO_(4)` electrolyte to change from a concentration of `34.6%` by weight (density `1.261 gmL^(-1)` at `25^(@)C`) to one of `27%` by weight. The original volume of electrolyte is one litre. How many faraday have left the anode of battry ? Note the water is produced by the cell reaction as `H_(2)SO_(4)` is used up. Over all reaction is :
`Pb_(s) + PbO_(2) + 2H_(2)SO_(4(l)) rarr 2PbSO_(4(s)) + 2H_(2)O`

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The correct Answer is:
`1.255` faraday
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A lead storage cell is discharged which causes the H_(2)SO_(4) electrolyte to change from a concentration of 34.6% by weight (density 1.261gml^(-1) at 25^(@)C ) to one of 27% by weight. The original volume of electrolyte is one litre. Calculate the total charge released at anode of the battery. Note that the water is produced by the cell reaction as H_(2)SO_(4) is used up. over all reaction is. Pb(s)+PbO_(2)(s)+2H_(2)SO_(4)(l)to2PbSO_(4)(s)+2H_(2)O(l)

Equivalent weight of H_(2)SO_(4) in the following reaction (Pb(s) + PbO_(2)(s) + H_(2)SO_(4) rightarrow PbSO_(4) + H_(2)O is

A fully charged lead-storage battery contains 1.5L of 5M H_(2)SO_(4) . During discharging of lead-storage acid battery, following reaction takes place: Pb(s)+PbO_(2)(s)+2H_(2)SO_(4)rarr2PbSO_(4)(s)+2H_(2)O

A fully charged lead-storage battery contains 1.5L of 5M H_(2)SO_(4) . During discharging of lead-storage acid battery, following reaction takes place: Pb(s)+PbO_(2)(s)+2H_(2)SO_(4)rarr2PbSO_(4)(s)+2H_(2)O

If 1 litre aq. Solution of H_(2)SO_(4) ( 10% by weight) with density 1.1 gm/ml, find th pH of solution.

During the discharge of a lead storage battery, the density of sulphuric acid fell from 1.294 g mL^(-1) to 1.139 g mL^(-) . Sulphuric acid of density 1.294 g mL^(-1) is 39% by weight and that of density 1.139 g mL^(-1) is 20% by weight. The battery hold 3.5 litre of acied and discharge. Calculate the no. of ampere hour for which the battery must have been used. The charging and discharging reactions are: Pb+SO_(4)^(2-) rarr PbSO_(4)+2e (charging) PbO_(2)+4H^(+)+SO_(4)^(2-)+2e rarr PbSO_(4)+2H_(2)O (discharging)

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