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Dissociation constant for Ag(NH(3))(2)^(...

Dissociation constant for `Ag(NH_(3))_(2)^(+)` into `Ag^(+)` and `NH_(3)` is `6 xx 10^(-14)`. Calculate `E^(@)` for the half reaction.
`Ag(NH_(3))_(2)^(+) + e rarr Ag + 2NH_(3)`
Given, `Ag^(+) + e rarr Ag` has `E^(@) = 0.799 V`

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The correct Answer is:
`+0.019 V ;`
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P BAHADUR-ELECTROCHEMISTRY-Exercise (9) ADVANCED NUMERICAL PROBLEMS
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