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Design the cell having one of the half r...

Design the cell having one of the half reaction `CuS + 2e rarr Cu + S^(2-)` and cell reaction
`CuS+2e rarr Cu+S^(2-)`
Also calculate `E_(Cu//CuS)^(@)` if `K_(SP)` of `Cu = 8.5 xx 10^(-36)`. Calculate the standard free energy change, `E_(cell)^(@)` for the cell reaction.
(Also given `E_(Cu//Cu^(2+))^(@) = -0.34 V`)

Text Solution

Verified by Experts

The correct Answer is:
`-1.035 V, -0.709, -199.755 kJ ;`
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