The density of crystalline `CsCl` is `3.988 g//cm^(3)`. The volume effectively occupied by a single `CsCl` ion pairs in the crystals is :(Given `CsCl` has mol. Mass `168.4`)

Options

A. `7.014xx10^(-23) cm^(3)`
B. `7.014xx10^(-20) cm^(3)`
C. `5.023xx10^(-23) cm^(3)`
D. `5.023xx10^(-20) cm^(3)`

Explanation

To find the volume effectively occupied by a single CsCl ion pair in the crystal, we can use the formula that relates density, molar mass, and volume. Here’s a step-by-step solution:

### Step 1: Understand the formula
The formula to calculate the volume occupied by a single ion pair in a crystal is given by:

\[ V = \frac{Z \times M}{\rho \times N_A} \]
...