The reaction of dimerisation of `NO_(2)` in `N_(2)O_(4)` is `2NO_(2)hArrN_(2)O_(4)`. The reaction is carried out by taking `1` mole each of `NO_(2)` and `N_(2)O_(4)` in a closed vessel of `1` litre at `400 K`. The equilibrium pressure was found to be `77 atm`.
The ratio of partial pressures of `NO_(2)` and `N_(2)O_(4)` at equilibrium is:

Options

A. `2.62`
B. `0.38`
C. `3.62`
D. `0.28`

Explanation

`P'_(NO_(2))=P_(T)xx(n_(NO_(2)))/(Sigman)`
`:. (P'_(NO_(2)))/(P'_(N_(2)O_(4)))=(n_(NO_(2)))/(n_(N_(2)O_(4)))=1.7/0.65=2.62`
`P'_(N_(2)O_(4))=P_(T)xx(n_(N_(2)O_(4)))/(Sigma n)`