Assuming the earth of to be a uniform sphere of radius `6400 kg` and density `5.5 g//c.c.`, find the value of `g` on its surface. `G=6.66xx10^(-11)Nm^(2)kg^(-2)`

Explanation

Here, `R = 6400 xx 10^(3) m = 6.4 xx 10^(6)m`, `rho = 5.5 g//c.c. = 5.5 xx 10^(3) kg//m^(3)`.
Now, `g = (GM)/(R^(2)) = (G)/(3) pi R^(3) xx rho = (4)/(3)pi GR_(rho) = (4)/(3) xx (22)/(7) xx 6.66 xx 10^(-11) xx 6.4 xx 10^(6) xx 5.5 xx 10^(3) = 9.82 ms^(-2)`