Assuming that the Earth is a sphere of radius `R`. At what altiude will the value of acceleration due to gravity be half its value at the surface of the Earth?

Explanation

`g' = (g)/(2) = (gR^(2))/((R + h)^(2))` or `(R + h)^(2) = 2 R^(2)`
or `R + h = sqrt(2) R` or `h = (sqrt(2)- 1)R`