One of the satellite of jupiter, has an orbital period of `1.769` days and the radius of the orbit is `4.22 xx 10^(8) m`. Show that mass of jupiter is about one thousandth times that of the radius of the sun. (Take `1` year `= 365.15` mean solar day).

Explanation

To find the mass of Jupiter based on the given orbital period and radius of its satellite, we can use Kepler's third law of planetary motion, which relates the orbital period of a satellite to the mass of the planet it orbits.

### Step-by-Step Solution:

1. **Convert the Orbital Period from Days to Seconds:**
\[ T = 1.769 \text{ days} \times 24 \text{ hours/day} \times 60 \text{ minutes/hour} \times 60 \text{ seconds/minute} \]
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