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The height at which the acceleration due...

The height at which the acceleration due to gravity becomes `(g)/(9)` (where g =the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth, is :

A

`R//sqrt(2)`

B

`R//2`

C

`R//sqrt(2)`

D

`2R`

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The correct Answer is:
D
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