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A geostationary satellite is orbiting th...

A geostationary satellite is orbiting the Earth at a height of `6 R` above the surface of Earth, where `R` is the radius of the Earth. The time period of another satellites is `6 sqrt(2) h`. Find its height from the surface of Earth.

Text Solution

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Here, `r_(1) = 6R + R = 7 R, T_(1) = 24 h, T_(2) = 6 sqrt(2) h`,
`r_(2) = r_(1) ((r_(2))/(r_(1)))^(3//2) = 7R((6sqrt(2))/(24))^(2//3) = 7R((1)/(2)) = 3.5 R`
`:.` Height of satellite from the surface of earth
`= 3.5 R - R`
`= 2.5 R`
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Knowledge Check

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