Find the percentage decrease in the weight of the body when taken to a depth of `32 km` below the surface of earth. Radius of the earth is `6400 km`.

Explanation

`g' = g (1- (d)/(R )) = g - g (d)/(R )`
`g - g' = gd//R`
`%` decrease in weight
`= ((mg - mg') xx 100)/(mg) = ((g - g')/(g)) xx 100`
`= (d)/(R ) xx 100 = (32)/(6400) xx 100 = 0.5%`