calculate the gravitaional intensity and graviational potential at a location which is from the surface of the Earth at a height `4` times the radius of the surface. `R_(e) = 6400 km`,
`G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) , M_(e) = 6 xx 10^(24) kg`.

Explanation

To calculate the gravitational intensity and gravitational potential at a height of 4 times the radius of the Earth, we will follow these steps:

### Step 1: Identify the given values
- Radius of the Earth, \( R_e = 6400 \, \text{km} = 6.4 \times 10^6 \, \text{m} \)
- Height above the Earth's surface, \( h = 4R_e = 4 \times 6.4 \times 10^6 \, \text{m} = 25.6 \times 10^6 \, \text{m} \)
- Total distance from the center of the Earth, \( r = R_e + h = 6.4 \times 10^6 + 25.6 \times 10^6 = 32 \times 10^6 \, \text{m} \)
- Gravitational constant, \( G = 6.67 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2 \)
- Mass of the Earth, \( M_e = 6 \times 10^{24} \, \text{kg} \)
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