The radius of a planet is `R`. A satellite revolves around it in a circle of radius `r` with angular velocity `omega_(0)`. The acceleration due to the gravity on planet's surface is

Explanation

Let `m` be the mass of the satellite. Then,
`m r omega^(2) = ((GM m)/(r^(2)))` or `GM = omega^(2) r^(3)`
Now `g = (GM)/(R^(2)) = (omega^(2)r^(3))/(R^(2))`