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particles of masses 2M m and M are resec...

particles of masses 2M m and M are resectively at points A , B and C with ` AB = (1)/(2) (BC)` m is much - much smaller than M and at time ` t=0` they are all at rest as given in figure . As subsequent times before any collision takes palce .

A

`m` will remains at rest.

B

`m` will move towards `M`

C

`m` will move towards `2 M`.

D

`m` will have oscillatory motion.

Text Solution

Verified by Experts

The correct Answer is:
C
Resultant force on mass `m` due to masses at `A` and `B` is `F = (G2M xx m)/((AB)^(2)) - (GMm)/((BC)^(2))` towards `BA`.
Therefore, `m` will move towards `2M`.
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