A solid ball 3 cm in diameter is submeraged in a lake at such a depth that the pressure exerted by water is `1 kg f//sq` cm. Find the change in volume of the ball if bulk modulus of ball is `10^7 dyn e//sqcm.`

Answer

1.386 c.c.

Explanation

`p = 1kg f//sq cm = 1000 xx 980 dyn e //sq cm`
`V = (4)/(3) pi r^3 = (4xx22xx(3//2)^3)/(3xx7)c.c.`
`Delta V = ? B = 10^7 dyn e //sq cm`. Use `Delta V = p V//B` and solve.