A rubber cube of side 8 cm has one side fixed, while a tangential force equal to the weight fo 300 kilogram is applied to the opposite face. Find the shearing strain produced and distance through which the strain side moves. Modulus of rigidity for rubber is `2xx10^7 dyn e cm^(-2)`

Answer

0.23 rad, 1.84 cm

Explanation

Here, L = 8cm, `F = 300 kg f = 300 xx 10000 xx 980 dyn e`, `G = 2xx10^7 dyne cm^(-2)`
As, `G = (F)/(L^2 theta) theta = (F)/(L^2G) = (300 xx 1000 xx 980)/((8)^2 xx 2xx10^7)`
`= 0.23 rad" "Delta = L theta = 8 xx 0.23 = 1.84 cm`