Two parallel and opposite forces each 5000 N are applied tangentially to the upper and lower faces of a cubical metal block of side 25 cm. the angle of shear is (The shear modulus of the metal is 80 Gpa)

Answer

`6.94 xx 10^(-7) ; 2.08 xx 10^(-7)m`

Explanation

Shearing stress `= (F)/(L^2)` Shearing strain, `theta = ("shearing stress")/("shear modulus")`
` = (F//L^2)/(G) = (F)/(L^2G)`
`= (5000)/((0.30)^2 xx 8xx10^(10)) = 69.4 xx 10^(-8)`
` =6.94 xx 10^(-7)` Displacement of upper surface `Delta L = L theta`
` =0.30 xx 6.94xx10^(-7) = 2.08xx10^(-7)m`