A wire suspended vertically from one of itsends is strached by attached a weight of `200 N` to the lower end . The weight streches the wire by `1 mm` . Then the elastic energy stored in the wire is

Answer

0.1 J

Explanation

Elastic potential energy` U = (1)/(2)xx` stress `xx` strain `xx `volume
`:. U = (1)/(2) xx(F)/(A)xx(Delta l)/(l)xxAl = (1)/(2) F Delta l`
` =(1)/(2) xx 200 xx 10^(-3) = 0.1 J`