A barometer kept in an alevator ac celerating upward reads 76 cm of mrecury. If the elevator is ac celerating upwards at `4.5ms^(-2)` find the air pressure in the elevator in cm of mercury. Density of mercuty ` =13.6 xx 10^3 kg m^(-3) G = 9.8 m//s^2`

Answer

111 cm of Hg

Explanation

When elevator moves upwards with ac celeration a then effection ac celeration = g+a Pressure ` = h rho (g+a)`
` =0.76 xx(13.6 xx 10^3) xx(9.8 + 4.5)`
` = (0.76xx13.6xx10^3 xx14.3)/(9.8xx(13.6xx10^3))m" of "Hg`
` = 1.11 m" of "Hg = 111 cm" of "Hg`