A tank 5 m high is half filled with water and then is filled to top with oil of density `0.85 g//cm^3` The pressure at the bottom of the tank, due to these liquids is

Answer

`462.5 g wt. cm^(-2)`

Explanation

`Pressure = ("total weight of water and liquid")/("base area of tank")`
`A xx (500//2)xx1xx980`
` = (+Axx500//2)xx0.85xx(980)/(A) dyn e //cm^2`
` =(250 xx 980 + 250 xx0.85 xx 980)/(980)g" wt "cm^(-2)`
` = 462.5 g wt. cm^(-2)` Alternative method, Average density =` (0.85 xx 250 + 1 xx 250)/(500)`
=` 0.925 g//c.c`. `P = h rho g = 500xx0.925 xx 980`
`= 462.5 xx 980 dyn e//cm^2`
` =462.5 g wt. cm^(-2)`