The neck and the bottom of a bottal of a bottle filled with incompressible liquid are 3 cm and 8 cm in diameter respectively. If the cork is pressud with a force 1.4 kg f in the neck of the bottle, find the force exerted on the bottom of the liquid.

Answer

9.95 kg f

Explanation

Here, `2R_1 = 3 cm or R_1 = 1.5 cm = 1.5 xx 10^(-2) m`
`R_2 = 8//2 = 4 cm = 4xx10^(-2)m,`
`F_1 = 1.4 kg f = 1.4 xx 9.8 N`
`F_2 = (F_1)/(pi R_1^2) xx pi R_2^2`
`F_2 = F_1 (R_2^2)/(R_1^2)= (1.4 xx9.8)xx(4xx10^(-2))/(1.5 xx 10^(-2))^2`
`= 9.95 xx 9.8 N = 9.95 kg f`