Water rises in a capillary tube to a height 2.0 cm. In an another capillary tube whose radius is one third of it, how much the water will rise ? If the first capillary tube is inclined at an angle of `60^@` with the vertical then what will be the position of water in the tube.

Answer

6.0 cm ; 4.0 cm

Explanation

`h = 2 S cos theta//r rho g`
or `h r = 2 S cos theta//rho g =` a constant `:. H_1 r_2 = hr or h_1 = hr//r_1 = hr//(r//3)`
`= 3h = 3xx 2.0 = 6.0 cm` Let length of water in the capillary tube be `h_2` in the inclined position, the vertical height h ( = 2.0 cm) of the liquid will remain the same. Then `h_2 = h//cos 60^@ = 2(1//2) = 4.0 cm`