What is the power requird to raise 300 liters of water per minute through a height of 6 m using a pipe of diameter 2.5 cm ? `g = 10 m//s^2.`

Answer

600 watt.

Explanation

Workdone against gravity `W_1 = mgh = V rho gh` Workdonw againsty pressure difference is `W_2 = Delta PxxV= h rho g xx V = V rho gh.`
Total workdonw, `W = W_1 + W_2 = 2 V rho gh` Power spend, `(W)/(t) = (2V rho gh)/(t) = (2xx(300 xx 10^(-3) xx 10^3 xx 10 xx6)/(60))`
= 600 watt