A squre metal plate of 10cm side moves parallel to another plate with a velocity of `10cm s^(-1),` both plates immersed in water. If the viscous force is 200 dyne and viscosity of water is 0.01 poise, what is their distance a part.

Answer

0.05 cm

Explanation

Here, `A = 10 xx 10 = 100 sq cm`, `dupsilon = 10 cm^(-1), F =200 dyn e,`
`eta = 0.01 poise, dx =?`
`F = eta A =(dupsilon)/(dx)` or `dx = (eta A d upsilon)/(F) = (0.01xx100 xx10)/(200)`
` - 0.05 cm`