Calculate the total energy possessed by one kg of water at a point where the pressure is `30 gf//mm^(2)`, velocity is `0.1 ms^(-1)` and height is `60 cm` above the ground level.

Explanation

To calculate the total energy possessed by 1 kg of water at a given point, we need to consider three forms of energy: pressure energy, gravitational potential energy, and kinetic energy. Let's break down the calculation step by step.

### Step 1: Convert Pressure to SI Units
The pressure given is \(30 \, \text{gf/mm}^2\). We need to convert this to pascals (Pa), the SI unit of pressure.

\[ 1 \, \text{gf} = 9.8 \, \text{N} \]
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