Water flow through a horizontal pipe. The area of cross-second at one place `A_(1)=10 cm^(2)`, velocity of water flow is `1 ms^(-1)` and pressure is `2000` Pa. At another place area `A_(2)=5 cm^(2)`. Whate is the pressure at area `A_(2)` ?

Explanation

To find the pressure at area \( A_2 \) in a horizontal pipe where water is flowing, we can use the principles of fluid dynamics, specifically the continuity equation and Bernoulli's equation.

### Step-by-Step Solution:

1. **Identify Given Values:**
- Area at point 1, \( A_1 = 10 \, \text{cm}^2 = 10 \times 10^{-4} \, \text{m}^2 = 0.0010 \, \text{m}^2 \)
- Velocity at point 1, \( V_1 = 1 \, \text{m/s} \)
- Pressure at point 1, \( P_1 = 2000 \, \text{Pa} \)
...