If each square metre, of sun's surface radiates energy at the rate of `6.3xx10^(7) jm^(-2) s^(-1)` and the Stefan's constant is `5.669xx10^(-8) Wm^(-2) K^(-4)` calculate the temperature of the sun's surface, assuming Stefan's law applies to the sun's radiation.

Answer

`[5773 K]`

Explanation

Here, `E=6.3xx10^(7) jm^(-2) s^(-1)`,
`sigma =5.669xx10^(-8) Wm^(-2) K^(-4)`
`E=sigma T^(4)`
or `T=((E)/(sigma))^(1//4)= [(6.3xx10^(7))/(5.669xx10^(-8))]^(1//4) =5773 K`