What is the density of lead under a pressure of `2.0xx10^(8) N//m^(2) ` , if the bulk modulus of lead is ` 8.0xx10^(9) N//m^(2)` and initially the density of lead is `11.4 g//cm^(3)`?

Options

A. `11.3 g//c.c.`
B. `11.5 g//c.c.`
C. `11.6 g//c.c.`
D. `11.7 g//c.c.`

Answer

D

Explanation

`rho=(M)/(V)` or `rho prop(1)/(V)` `:. (rho')/(rho)=(V)/(V')=(V)/(V+Delta V)`
or `rho'=rho((V)/(V+Delta V))=rho ((1)/(1+Delta V//V))`
`:. B=(-Delta P)/(Delta V//V)`' so
`rho'=rho((1)/(1-Delta P//B))`
`11.4[(1)/(1-(2.0xx10^(8)//8.0xx10^(9)))] =11.7 g//c.c.`