In the above question, the position of point D from end A of the rod at which there is equal strain on both the wires is

Options

A. `1.0 m`
B. `(2//3)m`
C. `(4//3)m`
D. `(5//3)m`

Answer

A

Explanation

Given, strain in steel= strain in brass
`(T_(s)//A_(s))/(Y_(s))=(T_(B))//(A_(B))/(Y_(B))`
or `(T_(s))/(T_(B))=(A_(s)Y_(s))/(A_(B)Y_(B))=((1xx10^(-3))(2xx10^(11)))/((2xx10^(-3))(1xx10^(11)))=1`
Taking moments of forces about point D, we have
`T_(s)x=T_(B)(2-x)`
or `(T_(s))/(T_(B))=((2-x)/(x))` or `1=(2-x)/(x)` or `x=1m`