A piece of solid weighs 120 g in air, 80 g in water and 60 g in a liquid. The relative density of the solid and that of the liquid are respectively

Options

A. 3,2
B. `2,3//4`
C. `3//2,2`
D. `3,3//2`

Explanation

To solve the problem, we will calculate the relative density of the solid and the liquid step by step.

### Step 1: Calculate the Relative Density of the Solid
The formula for the relative density (RD) of a solid is given by:

\[ \text{Relative Density of Solid} = \frac{\text{Weight in Air}}{\text{Weight in Air} - \text{Weight in Water}} \]

Given:
- Weight in Air = 120 g
- Weight in Water = 80 g

Substituting the values:

\[ \text{Relative Density of Solid} = \frac{120 \, \text{g}}{120 \, \text{g} - 80 \, \text{g}} = \frac{120 \, \text{g}}{40 \, \text{g}} = 3 \]

### Step 2: Calculate the Relative Density of the Liquid
The formula for the relative density of a liquid is given by:

\[ \text{Relative Density of Liquid} = \frac{\text{Weight in Air} - \text{Weight in Liquid}}{\text{Weight in Air} - \text{Weight in Water}} \]

Given:
- Weight in Liquid = 60 g

Substituting the values:

\[ \text{Relative Density of Liquid} = \frac{120 \, \text{g} - 60 \, \text{g}}{120 \, \text{g} - 80 \, \text{g}} = \frac{60 \, \text{g}}{40 \, \text{g}} = \frac{3}{2} \]

### Final Result
Thus, the relative densities are:
- Relative Density of the Solid = 3
- Relative Density of the Liquid = \(\frac{3}{2}\)

### Summary
The relative density of the solid and that of the liquid are respectively 3 and \(\frac{3}{2}\).

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