A capillary tube of radius `r` is immersed in a liquid. The liquid rises to a height `h`. The corresponding mass is `m`. What mass of water shall rise in the capillary if the radius of the tube is doubled?

Options

A. 2 M
B. M
C. `M//2`
D. 4 M

Answer

A

Explanation

Since `h=(2S cos theta)/(r rho g)` , i.e., `h prop(1)/(r)`, therefore r becomes 2 r, h becomes `(h)/(2)`. Mass of the water in tube = volume x density `=pi(2r)^(2) (h)/(2) rho`
`=2 pi r h rho =2M`