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The lower end of a capillary tube of rad...

The lower end of a capillary tube of radius r is placed vertically in water of density `rho` , surface tension S. The rice of water in the capillary tube is upto height h, then heat evolved is

A

`+(pi^(2)r^(2)h^(2)rho g)`

B

`+(pi r^(2)h^(2)rho g)/(2j)`

C

`-(pip^(2)r^(2)h^(2)rho g)/(2j)`

D

`-(pi r^(2)h^(2)rho g)/(j)`

Text Solution

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The correct Answer is:
To solve the problem of finding the heat evolved when water rises in a capillary tube, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Capillary Rise:** The height \( h \) to which water rises in a capillary tube is given by the formula: \[ h = \frac{2S \cos \theta}{\rho g r} \] where \( S \) is the surface tension, \( \theta \) is the contact angle, \( \rho \) is the density of the liquid, \( g \) is the acceleration due to gravity, and \( r \) is the radius of the capillary tube. 2. **Calculating the Upward Force:** The upward force \( F \) acting on the water column in the capillary tube can be expressed as: \[ F = 2\pi r S \cos \theta \] 3. **Calculating the Work Done:** The work done \( W \) against this force when the water rises to height \( h \) is: \[ W = F \cdot h = (2\pi r S \cos \theta) \cdot h \] 4. **Substituting for Height \( h \):** Substitute the expression for \( h \) into the work done equation: \[ W = (2\pi r S \cos \theta) \cdot \left(\frac{2S \cos \theta}{\rho g r}\right) \] Simplifying this gives: \[ W = \frac{4\pi S^2 \cos^2 \theta}{\rho g} \] 5. **Calculating Potential Energy Stored:** The potential energy \( U \) stored in the water column can be calculated as: \[ U = mgh = \left(\pi r^2 h \rho\right) \cdot g \cdot \frac{h}{2} \] Substituting for \( h \): \[ U = \pi r^2 \left(\frac{2S \cos \theta}{\rho g r}\right) \rho g \cdot \frac{h}{2} \] Simplifying gives: \[ U = \frac{\pi r^2 \cdot 2S \cos \theta \cdot \rho g}{\rho g} \cdot \frac{2S \cos \theta}{\rho g} \] 6. **Calculating Heat Evolved:** The heat evolved \( Q \) can be expressed as: \[ Q = W - U \] Substituting the values of \( W \) and \( U \): \[ Q = \frac{4\pi S^2 \cos^2 \theta}{\rho g} - \frac{\pi r^2 \cdot 2S \cos \theta \cdot \rho g}{\rho g} \] 7. **Final Expression for Heat Evolved:** After simplifying the above expression, we arrive at the final formula for heat evolved: \[ Q = \frac{\pi r^2 h^2 \rho g}{2} \] ### Conclusion: The heat evolved when water rises in the capillary tube can be expressed as: \[ Q = \frac{\pi r^2 h^2 \rho g}{2} \]

To solve the problem of finding the heat evolved when water rises in a capillary tube, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Capillary Rise:** The height \( h \) to which water rises in a capillary tube is given by the formula: \[ h = \frac{2S \cos \theta}{\rho g r} ...
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