The cylinderical tube of a spray pump has radius R, One end of which has n fine holes, each of radius r. If the speed of the liquid in the tube is V, the speed of the ejection of the liquid through the holes is :

Options

A. `(V^(2)R)/(nr)`
B. `(VR^(2))/(n^(2)r^(2))`
C. `(VR^(2))/(nr^(2))`
D. `(VR^(2))/(n^(3)r^(2))`

Answer

C

Explanation

Ac cording to equation of continutiy volume of inflow rate = volume of outflow rate
`pi R^(2) V=n pi r^(2) v'` or `v'=(pip R^(2)V)/(n pi r^(2)) = (VR^(2))/(nr^(2))`