A cylinder containing one gram molecule of the gas was compressed adiabaticaly untill its tempertaure rose from `27^(@)C` to `97^(@)C`. Calculate the work done and heat produced in the gas `(gamma=1.5)`.

Explanation

Here, initial temperature,
`T_(1)= 27^(@)C= 273+27= 300K`
final temperature,
`T_(2)= 97^(@)C= 273+97= 370K`.
When a gas is compressed adiabatically, work done on gas is given by
`W=R/((1-gamma))(T_(2)-T_(1))`
`=(8.3xx(370-300))/(1-1.5)`
`= -11.62xx10^(2)J`
`:.` Heat produced,
`H= (-W)/J= (11.62xx10^(2))/(4.2)= 276.7cal`.