Three moles of an ideal gas kept at a constant temperature of `300K` are compressed from a volume of 4 litre to 1 litre. Calculate work done in the process. `R= 8.31 J mol e^(-1)K^(-1)`.

Explanation

Here, `n=3, T= 300K`
`V_(1)= 4 litre, V_(2) = 1 litre, W=?`
`W= 2.3026nRT log(V_(2)//V_(1))`
`= 2.3026xx3xx8.31xx300log(1/4)`
`W=2.3026xx3xx8.31xx300(-0.6021)`
`= -1.037xx10^(4)J`
Negative sign shows that work is done on the gas.