A carnot engine whose heat sink is at `27^(@)C` has an efficiency of `40%`. By how many degrees should the temperature of source be changed to increase the efficiency by `10%` of the original efficiency?

Explanation

To solve the problem step by step, we will follow the principles of the Carnot engine and the formula for efficiency.

### Step 1: Understand the Given Data
- The heat sink temperature (T2) is given as 27°C.
- The efficiency (η) of the Carnot engine is 40%, which can be expressed as a decimal: η = 0.40.
- We want to increase the efficiency by 10% of the original efficiency, which means the new efficiency (η') will be 40% + 4% = 44%.

### Step 2: Convert the Heat Sink Temperature to Kelvin
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