A carnot engine absorbs `500J` of heat from a reservoir at `227^(@)C` and rejects of seek (ii) efficiency of engine (iii) amount of useful work done per cycle.

Explanation

Here, `Q_(1)=500J`
`T_(1)= 227^(@)C=227+273= 500K`
`Q_(2)= 300J, T_(2)=?, eta=?, W=?`
As `(T_(2))/(T_(1))= (Q_(2))/(Q_(1))= (300)/(500)`,
`T_(2)= 6/(10)T_(1)= 6/(10)xx500= 300K`
`=(300-273)^(@)C= -27^(@)C`
`eta=1 - (T_(2))/(T_(1))=1 - (6)/(10)= 4/(10)= 40%`
`W=Q_(1)-Q_(2)= 500-300= 200J`