A refrigerator has to transfer an average of 263J of heat per second from temperature `-10^@C` to `25^@C`. Calculate the average power consumed, assuming no enegy losses in the process.

Explanation

Here, `Q_(2)= 263Js^(-1)`
`T_(2)= -10^(@)C= -10+273= 263K`
`T_(1)=25^(@)C=25+273= 298K`
Power required = work/sec(W)= ?
As `beta=(Q_(2))/W= (T_(2))/(T_(1)-T_(2))`
`:. W=(Q_(2)(T_(1)-T^(2)))/(T_(2))`
`=(263(298-263))/(263)= (263xx35)/(263)`
`W=35Js^(-1)= 35 "watt" `