One mole of an ideal gas is heated from 273K to 546K at constant pressure of 1 atmosphere. Calculate the work done by the gas in the process.

Answer

`2.26xx10^(3)J`

Explanation

For one mole of an ideal gas,
`(V_(2))/(T_(2))=(V_(1))/(T_(1)) :. V_(2)= (V_(1))/(T_(1))xxT_(2)= 22.4xx10^(-3)xx(546)/(273)`
`V_(2)= 44.8xx10^(-3)m^(3)`
`W=P(V_(2)-V_(1))`
`=1.01xx10^(5)(44.8-22.4)xx10^(-3)`
`W=2.26xx10^(3)J`