A perfect carnot engine has source temp. `227^(@)C` and sink temp. `127^(@)C`. Find the efficiency of the engine, If `10000J` of external work is to be done, find heat received from source and heat released to the sink.

Answer

`20% ; 5xx10^(4) ; 4xx10^(4)J`

Explanation

Here, `T_(1)=227^(@)C=(227+273)K=500K`
`T_(2)=127^(@)C=(127+273)K=400K`
`eta= 1 -(T_(2))/(T_(1))=1 -(400)/(500)=1/5= 20%`
`W=10000J, Q_(1)?, Q_(2)=?`
`eta=W/(Q_(1)), Q_(1)=W/(eta)= (10000)/(20//100)= 5xx10^(4)J`
`Q_(2)=Q_(1)-W=5xx10^(4)-10000= 4xx10^(4)J`