Calculate the heat absorbed by a system in going through the cyclic process shown in figure ,

Answer

`31.4 J`

Explanation

Work done in a cyclic process, (figure)
`=` area of the curve representing the process
`=pir^(2)=pi((DeltaP)/2)((DeltaV)/2)`
`=3.14((300-100)/2)xx10^(3)xx((300-100)/2)xx10^(-6)`
`=31.4 joule`