In a refrigerator, heat from inside at `270 K` is transferred to a room at `300 K`. How many joule of heat energy is drawn from the sink for each joule of electrical energy consumed ideally ?

Explanation

To solve the problem, we will use the concept of the Coefficient of Performance (COP) of a refrigerator. The COP is defined as the ratio of the heat removed from the cold reservoir (Q2) to the work input (W).

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Temperature of the cold reservoir (T2) = 270 K
- Temperature of the hot reservoir (T1) = 300 K
- Work done (W) = 1 Joule
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