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During adiabatic expension of 10 mol es ...

During adiabatic expension of `10 mol es` of a gas , internal energy decrease, by `700 J`. Work done during the process is `xxx10^(2) J`. What is `x`?

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From firsrt law of thermodynamics, `dQ= dU+dW`
In adiabatic expression, `dQ=0`
`:. dW= -dU= -(-700 J)= 700 J= 7xx10^(2)J`
`:. X= 7`
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