What will be the root mean square speed of helium at `40^(@) C`, if mean square speed of oxygen molecule at `0^(@) C is 460 m//s`? Molecule weight of oxygen is `32 g//"mole"` and of helium is ` 4 g//"mole"`.

Explanation

To find the root mean square (RMS) speed of helium at \(40^\circ C\), we can use the relationship between the RMS speed of different gases, given their molecular weights and temperatures. Here’s a step-by-step solution:

### Step 1: Understand the formula for RMS speed
The formula for the root mean square speed (\(v_{rms}\)) of a gas is given by:
\[ v_{rms} = \sqrt{\frac{3RT}{M}} \]
where:
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