The volume of vessel A is twice the volume of another vessel B and both of them are filled with the same gas. If the gas in A is at twice the temperature and twice the pressure in comparison to the gas in B, what is the ratio of number of gas molecule in A and B ?

Explanation

Here, `V_(A) = 2 V_(B), T_(A) = 2 T_(B) , P_(A) = 2 P_(B)`,
`(P_(A)V_(A))/(T_A) = n_(A)R and (P_(B)V_(B))/(T_B) = n_(B)R`
`:. (n_A)/(n_B) = (P_(A)V_(A)T_(B))/(P_(B)V_(B)T_(A)) = ((2P_(B))(2V_(B))T_(B))/(P_(B)V_(B)(2T_(B))) = 2`.