Kinetic energy of translation of molecules of a gas having volume V and pressure P is 100 J. If same volume V of gas were at pressure 2 P, what would be the KE of translation ?

Explanation

If E is translation KE per unit volume, then
`E = 1/2 rho C^(2)`
and `P = 1/3 rho C^(2)`
`:. E = (3P)/(2)`
Now `EV = (3PV)/(2) = 100 joule`.
When P is double, K energy would become 200 "Joule".