A vessel A contains hydrogen and another vessel B whose volume is twice that of A contains same mass of oxygen at same temperature. Compare
(i) average KE of hydrogen and oxygen molecule.
(ii) root mean square speeds of molecules
(iii) pressure of gases in A and B.
Molecular weight of hydrogen and oxygen are 2 and 32 respectively.

Answer

`32:1`

Explanation

(i) As the two gases are at the same temperature, therefore average KE of molecules `(=3/2 kT)` is same. The desired ratio = 1:1
(ii) As `C = sqrt((3RT)/(M))`
`:. (C_H)/(C_("oxy")) = sqrt((M_("oxy"))/(M_H)) = sqrt((32)/(2)) = 4:1`
(iii) As `P = 1/3 M/V C^(2)`
and masses of two gases are equal.
`:. (P_H)/(P_("oxy")) = (V_O)/(V_H) xx ((C_H)/(C_O))^(2) = 2/1 xx (4/1)^(2) = 32:1`