Calculate the rms velocity of molecules of a gas of density `1.5 g litre^(-1)` at a pressure of `2 xx 10^(6) N//m^(2)`.

Answer

`2 xx 10^(3)m//s`

Explanation

Here, `C=? "Rho" = 1.5 g "litre"^(-1) = 1.5 kg m^(-3)`
`P= 2xx10^(6) N//m^(2)`
As `C=sqrt((3P)/(rho)) = sqrt((3 xx 2 xx 10^(6))/(1.5)) = 2 xx 10^(3)m//s`