If root mean sqauare velocity of the molecules of hydrogen at NTP is `1.84 kms^(-1)`, calculate the rms velocity of oxygen molecules at NTP. Molecular weights of hydrogen and oxygen are 2 and 32 respectively.

Answer

`0.46 km s^(-1)`

Explanation

`P=1/3 M/V C^(2)`
or `MC^(2) = 3 PV = 3 RT = a "constant" at STP`
Hence , `C prop 1//sqrt(M)`
Thus `(C_0)/(C_H) = sqrt((M_H)/(M_0)) = sqrt((2)/(32)) = 1/4`
or `C_(0)= (C_H)/(4) = 1.84/4 = 0.46 km s^(-1)`